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Two equal point charges A and B are R distance apart. A third point charge placed on perpendicular bisector at a distance d from the centre will experience max electrostatic force when?????

Aditi Dutta , 10 Years ago
Grade 12
anser 2 Answers
Saurabh Kumar

Last Activity: 10 Years ago

Calculate electric field at equitorial position ‘d’, then calculate net force exp by third point charge..
You will get a mathematical equation, then you differentiate the eqn w.r.t. d and put it equal to zero...
then find the value of d..............
ankit singh

Last Activity: 5 Years ago

 
A third point charge placed on the perpendicular bisector at a distance 'd' from the centre. Let charge on each particle is q and charge on third particle is Q. but only y = R/22 , d²F/dy² force will be maximum. so, at y = R/22 electrostatic force will be maximum.
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