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Two coducting sphetes of radii 3cm and 1cm qre separated by a distance of 10cm in free space.If the spheres are charged to same potential of 10V each ,the force of repulsion between them is

Two coducting sphetes of radii 3cm and 1cm qre separated by a distance of 10cm in free space.If the spheres are charged to same potential of 10V each ,the force of repulsion between them is

Grade:12

1 Answers

Arun
25763 Points
2 years ago
f q₁ is the charge on the first sphere, the potential at its surface is: 
V₁ = kq₁/r₁ 
q₁ = V₁r₁/k 

Similarly for the 2nd sphere: 
q₂ = V₂r₂/k 

If the centres of the spheres are a distance d apart the force between the spheres is: 
F = kq₁q₂/d² 
= k(V₁r₁/k)(V₂r₂/k)/d² 
= V₁r₁V₂r₂/(kd²) 

Since V₁ = V₂ (=V) this becomes: 
F = V²r₁r₂/(kd²) 

Just stick the values in (remember distances must be converted to metres).

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