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Grade 12Electrostatics

Two coducting sphetes of radii 3cm and 1cm qre separated by a distance of 10cm in free space.If the spheres are charged to same potential of 10V each ,the force of repulsion between them is

Profile image of Lubna
8 Years agoGrade 12
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1 Answer

Profile image of Arun
8 Years ago
f q₁ is the charge on the first sphere, the potential at its surface is: 
V₁ = kq₁/r₁ 
q₁ = V₁r₁/k 

Similarly for the 2nd sphere: 
q₂ = V₂r₂/k 

If the centres of the spheres are a distance d apart the force between the spheres is: 
F = kq₁q₂/d² 
= k(V₁r₁/k)(V₂r₂/k)/d² 
= V₁r₁V₂r₂/(kd²) 

Since V₁ = V₂ (=V) this becomes: 
F = V²r₁r₂/(kd²) 

Just stick the values in (remember distances must be converted to metres).

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