two cells of EMF E1 and E2 and internal resistance R1 and R2 are connected in parallel between the points A and B deduce the expression for the equivalent emf of the combination

Question

Arun · Answer

Given, Emf of first cell = E 1 Emf of second cell = E 2 Internal resistances of two cell are r 1 and r 2 respectively. Load resistance = R Effective emf is given by, E eff = E 1 r 1 + E 2 r 2 r 1 + r 2 Effective internal resistance, r eff = r 1 r 2 r 1 + r 2 Now, the total resistance of the circuit would be the sum of load resistance and effective internal resistance. R total = R + r eff = R + r 1 r 2 r 1 + r 2 Current through the load will be the same as the current through the circuit. Thus, I = E eff R total = E 1 r 1 + E 2 r 2 r 1 + r 2 R + r 1 r 2 r 1 + r 2 = E 1 r 1 + E 2 r 2 R ( r 1 + r 2 ) + r 1 r 2 which is the required expression for the current through the load.

Kushagra Madhukar · Answer

Dear student, Please find the answer to your question. Given, Emf of first cell = E1 Emf of second cell = E2 Internal resistances of two cell are r1 and r2 respectively. Load resistance = R Effective emf is given by, Eeff = E1r1 + E2 r2r1 + r2 Effective internal resistance, reff = r1 r2r1 + r2 Now, the total resistance of the circuit would be the sum of load resistance and effective internal resistance. Rtotal = R + reff = R + r1r2r1+r2 Current through the load will be the same as the current through the circuit. Thus, I = EeffRtotal = E1r1 + E2r2r1 +r2R+ r1r2r1 + r2 = E1r1 + E2 r2R(r1+r2) + r1r2 which is the required expression for the current through the load Thanks and regards, Kushagra

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

two cells of EMF E1 and E2 and internal resistance R1 and R2 are connected in parallel between the points A and B deduce the expression for the equivalent emf of the combination

two cells of EMF E1 and E2 and internal resistance R1 and R2 are connected in parallel between the points A and B deduce the expression for the equivalent emf of the combination

2 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electrostatics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

two cells of EMF E1 and E2 and internal resistance R1 and R2 are connected in parallel between the points A and B deduce the expression for the equivalent emf of the combination

two cells of EMF E1 and E2 and internal resistance R1 and R2 are connected in parallel between the points A and B deduce the expression for the equivalent emf of the combination

2 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electrostatics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship