Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        Three identical charges are fixed at the corners of an equilateral triangle  If the force between any two charges is F then the net electric force on any one of them 1)  root 2F2)  2F3)  root 3 F4)  3F
4 months ago

Piyush Kumar Behera
432 Points
							This is a vector addition question.As each of the particle is exering an repulsive force on each other of magnitude F.As the triangle given is an equilateral triangle. Hence the angle between the two forces is 60 degrees. So net force = $\sqrt{F^{2}+F^{2}+2F^{2}cos(60)}$Hence the answer is third opption$\sqrt{3}F$

4 months ago
Kiran Chauhan
24 Points
							As the charges are same. So they will repel each other. Here the triangle is equilateral. So the angle made will be 60 degree. Hence net force=√f2+f2+2×f×fcos60=√2f2+2f2×1/2=√3f2=√3×f  Hence root 3×f is the answer.

4 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Electrostatics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions