Electrostatics

Three equal charges 2×10^(-6) C each are held fixed at the three corners of an equilateral triangle of side 5cm. Find the Coulomb force experienced by one of the charges due to the rest two.

Technical GURUJI

8 Years agoGrade

2 Answers

Arun

8 Years ago

The resultant force on charge Q because of two equal forces because of other two Q charges planed on equilateral triangle will be given as:-
Fnet = 2Fcos(ϴ/2) ---------------(1)
F=kQ1Q2/r2 --------(2)
in this question Q1=Q2 =Q3 =Q
Given
Q=2 *10-6 c
K=9*109 N-m2/c2
r= .05 m
ϴ =60 degree
By using equation 1 and 2 and given quantities
Fnet = 2(9*109 *(2 *10-6 )2/(.05)2 cos30
=24.94 N

Kushagra Madhukar

6 Years ago

Dear student,

Please find the solution to your problem below.

The resultant force on charge Q because of two equal forces because of other two Q charges planed on equilateral triangle will be given as:-

F_net = 2Fcos(ϴ/2) ---------------(1)
F = kQ1Q2/r2 --------(2)
in this question Q1 = Q2 = Q3 = Q
Given
Q = 2 *10-6 C
K = 9*109 N-m2/C2
r = .05 m
ϴ = 60^o
By using equation 1 and 2 and given quantities
F_net = 2(9*109 *(2 *10-6 )2/(.05)2 cos30^o
=24.94 N

Hope it helps.

Thanks and regards,

Kushagra