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three +20uC charges are placed along a straight line,succesive charges being 2m apart.what is the force on the charge on the right end ?
force=(k*20*20/4^2 +k*20*20/2^2)*10^(-12)N =(400*k/16 +400*k/4)*10^(-12)N =125*k=125*9*10^9 *10^-12=1.125NSher Mohammadb.tech iit delhifaculty askiitians
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