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Grade 12th passElectrostatics

the potential difference on the surface of charged sphere radius R and between the distance 3r from the surface of a sphere is v the electric field at the distance which is equal to radius r from the surface will be

Profile image of altaf khan
7 Years agoGrade 12th pass
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1 Answer

Profile image of Khimraj
7 Years ago
potential at surface = KQ/r
potential at distance 3r from the surface = KQ/4r
KQ/r – KQ/4r = v
3KQ/4r = v
KQ/r = 4v/3
electric field at the distance which is equal to radius r from the surface = KQ/4r2 = (KQ/r)/(4r) = (4v/3)/(4r) = v/3r
Hope it clears............................
 

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