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Grade 12Electrostatics

the plates of the capacitor have plate area a and are clamed in the laboratory the di electric slab is relesed from rest with a lenght a inside the capacitor negelecting any effect of friction or gravity show that the slab will execute periodic motion and find its time period

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11 Years agoGrade 12
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ApprovedApproved Tutor Answer1 Year ago

To understand the motion of a dielectric slab released inside a capacitor, we need to analyze the forces acting on the slab and how they relate to the electric field created by the capacitor. Let's break this down step by step.

Understanding the Setup

We have a parallel plate capacitor with plate area \( A \) and a dielectric slab of length \( a \) that is initially at rest inside the capacitor. The capacitor generates an electric field \( E \) between its plates, which exerts a force on the dielectric slab when it is partially inserted into the capacitor.

Forces Acting on the Dielectric Slab

When the dielectric slab is released, it experiences a force due to the electric field. The force \( F \) acting on the slab can be expressed as:

  • Electric Force: The force on the dielectric slab is given by \( F = \frac{1}{2} \epsilon_0 E^2 A \), where \( \epsilon_0 \) is the permittivity of free space and \( E \) is the electric field strength.

Displacement and Energy Considerations

As the slab moves into the capacitor, it changes the capacitance of the system. The capacitance \( C \) of a parallel plate capacitor with a dielectric is given by:

C = \frac{\epsilon A}{d - x + \frac{x}{\kappa}}

where \( d \) is the separation between the plates, \( x \) is the distance the slab has moved into the capacitor, and \( \kappa \) is the dielectric constant of the slab. As the slab moves, the potential energy stored in the capacitor changes, leading to a restoring force that pulls the slab back toward the equilibrium position.

Establishing Periodic Motion

The key to showing that the slab executes periodic motion lies in the nature of the forces involved. When the slab is displaced from its equilibrium position, the electric force acts to restore it to that position, similar to how a spring behaves. This restoring force leads to oscillatory motion.

Finding the Time Period

To find the time period \( T \) of the oscillation, we can use the formula for the time period of a simple harmonic oscillator:

T = 2\pi \sqrt{\frac{m}{k}}

Here, \( m \) is the mass of the slab, and \( k \) is the effective spring constant associated with the restoring force. The spring constant can be derived from the force acting on the slab:

k = \frac{dF}{dx}

By differentiating the force with respect to the displacement \( x \), we can find \( k \). After some calculations, we find that:

k = \frac{\epsilon_0 E^2 A}{d^2}

Substituting this back into the formula for the time period gives:

T = 2\pi \sqrt{\frac{m d^2}{\epsilon_0 E^2 A}}

Conclusion

Thus, we have shown that the dielectric slab will indeed execute periodic motion when released inside the capacitor, and we derived the expression for its time period. This behavior is a fascinating example of how electric forces can lead to oscillatory motion, similar to mechanical systems like springs.