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The linear charge density on a dielectric ring of of radius r is varying with theta as lameda=lameda°(not) cos(theta/4).Find the total charge on the ring

The linear charge density on a dielectric ring of of radius r is varying with theta as lameda=lameda°(not) cos(theta/4).Find the total charge on the ring

Grade:12

1 Answers

sharad
33 Points
6 years ago
Just make a ring and mark it centre as o.Now from o take an theta of thickeness d(theta) so now the lenght taken on ring is rd(theta).As lameda=charge /lenght.And here lameda is not constant but changing with theta so we have to integerate .Let there be dq charge on the thickness rd(theta).So dq=lameda(not)×cos(theta/4)×rd(theta)And integerate left side 0 to q and right from 0 to pie.You will find answer 2(2)^1/2lameda(not)rBut net charge is 2 times of this as we integerate only a semicircle part.Therefore net charge is 4(2)^1/2lameda(not)r

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