Electrostatics> The force experienced by an unit charge w...

The force experienced by an unit charge when placed at a distance of 0.10m from the middle of an electric dipole on its axial line is 0.025N and when it is placed at a dustance of 0.2m the force is reduced to 0.002N. Calculate the dipole length

Shrutika , 6 Years ago

Grade 12

1 Answers

Khimraj

Last Activity: 6 Years ago

Let length of dipole is 2a then elecrtric field on axial line is given by

E = 2kpr/(r² – a²)²

Then

E1/E2 = (r1/r2)*((r2² – a²)²/(r1² – a²)²)

$\sqrt{E1*r2/E2*r1} = (r2^{2} - a^{2})/(r1^{2} - a^{2})$

$\sqrt{0.025*0.2/0.002*0.1} = (0.2^{2} - a^{2})/(0.1^{2} - a^{2})$

$5 = (0.2^{2} - a^{2})/(0.1^{2} - a^{2})$

0.05 – 5a² = 0.04 – a²

0.01 = 4a²

a = 1/20 m = 5 cm

then length = 2a = 10 cm.

Hope it clears If you like answer then please approve it.

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Electrostatics> The force experienced by an unit charge w...

The force experienced by an unit charge when placed at a distance of 0.10m from the middle of an electric dipole on its axial line is 0.025N and when it is placed at a dustance of 0.2m the force is reduced to 0.002N. Calculate the dipole length

Shrutika , 6 Years ago

Khimraj

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