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The force between two identical point charges in F. What will be the force if each charge is increased by 2 % and the distance between them is decreased by 3% ?

Rajesh Sodhi , 7 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Dear Student,
let r be the distance b/w the charges.
Then,
F = kq^2/r^2........(1)
After the changes in cahrges and the distance the new Force becomes:
F’= kq^2(1.02)^2/(0.98r)^2...............(2)
Divide both the eqns. we get,
F/F’= (0.98/1.02)^2
F’= (1.02/0.98)^2*F => 1.083F This would be the new Force.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

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