Electrostatics> The force between two charge when seprate...

The force between two charge when seprate by a distance of 50cm in air is 40 newton what will be the force between them if the distance becomes 25?

Amresh kumar , 8 Years ago

Grade 12

5 Answers

Maxx

158.4N..................m..................,..................................,.........!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Last Activity: 8 Years ago

DIWAKAR PANDEY

Dear, As given is F=kq1q2/r×r= Here we had changed r only So F is inversely proportional to r square. So F1/F2= 25×25/50×50 ( Cancel 50 with 25) F1=40(given) 40/F2=1/4 So F2=160

Last Activity: 8 Years ago

shubham singh

160 N is answer.....................mmm................................................................mmmmmmm.............................

Last Activity: 8 Years ago

Shailendra Kumar Sharma

F=Kq1q2/r2
so F1/F2=(r2)^2/(r1)^2
So F50 / F25= (25*25)/(50*50) =1/4
so the force at 25 cm will be 4 times of that at 50
so when distance is 25 the force will be 160N

Last Activity: 8 Years ago