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`        The coil consist of 90 ohm resistance and 127.3 mH inductance. Find the frequency of it when the impedance in the circuit is 50 ohm. (A) 75 Hz (B) 83 Hz (C) 50 Hz (D) 100Hz`
one year ago

Vikas TU
10049 Points
```							This is a simple L-R circuit.And the net impedence of such circuit is given b:Z= sq.root(90^2 +  (w*127.3*10^-3)^2) = 50sq both sides and solving we get,2500 = 8100 + 0.162w^20.162w^2 = – 5600the frequcny is coming negative which is not possible.Hence the given options contadicts.
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions