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Suppose that three point charges, q a , q b and q c are arranged at the vertices of a right-angled triangle, as shown in the diagram. What is the magnitude and direction of the electrostatic force acting on the third charge if q a = -0.6μC, q B = +4.0 μC, q c = +20 μC. Let a= 4.0 m, and b= 3.0 m? Answer: F(magnitude) = 77.4S exp -3 N, angle=2.53
Dear studentPlease find the link below and check solved examplehttps://www.askiitians.com/iit-jee-electrostatics/electric-potential-energy/Regards
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