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Spherical conductor with two linear and uniform dielectrics with relative permitivitty Ɛ r1 and Ɛ r2 is connected to constant voltage U . When second dielectric is removed, intensity of electric field by inner electrode is reduced by 1/3 , and electric field by outer electrode is increased two times. a=1.5mm, b=6mm, c=12mm . Calculate Ɛ r1 and Ɛ r2 . Result: Ɛ r1 =6, Ɛ r2 =3 Could someone help? Thanks for replies.

Spherical conductor with two linear and uniform dielectrics with relative permitivitty Ɛr1 and Ɛr2 is connected to constant voltage U. When second dielectric is removed, intensity of electric field by inner electrode is reduced by 1/3, and electric field by outer electrode is increased two times. a=1.5mm, b=6mm, c=12mm. Calculate Ɛr1 and Ɛr2.
 
Result:
Ɛr1=6, Ɛr2=3
 
Could someone help?
Thanks for replies.

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