0

Guest

Courses New

Question no 18 ....................,.............................

Question no 18 ....................,.............................

Question Image
Grade:11

1 Answers

Eshan
askIITians Faculty 2095 Points
4 years ago
Potential energy of the system with charge at the surface of the sphere=\dfrac{kQq}{R}.

Potential energy of the system with charge at the center of sphere=\dfrac{3}{2}\dfrac{kQq}{R}

From law of conservation of energy, the gain in electrostatic potential energy=loss in kinetic energy of charge
\implies \dfrac{3}{2}\dfrac{kQq}{R}-\dfrac{kQq}{R}=\dfrac{1}{2}mv^2
\implies \dfrac{1}{2} \dfrac{kQq}{R}=\dfrac{1}{2}mv^2
\implies v=\sqrt{\dfrac{Qq}{4\pi\epsilon_0 mR}}

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Electrostatics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More