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Electrostatics> Question no 18 ....................,........

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Question no 18 ....................,.............................

Chandan Kumar , 8 Years ago

Grade 11

1 Answers

Eshan

Potential energy of the system with charge at the surface of the sphere= $\dfrac{kQq}{R}$ .

Potential energy of the system with charge at the center of sphere= $\dfrac{3}{2}\dfrac{kQq}{R}$

From law of conservation of energy, the gain in electrostatic potential energy=loss in kinetic energy of charge
$\implies \dfrac{3}{2}\dfrac{kQq}{R}-\dfrac{kQq}{R}=\dfrac{1}{2}mv^2$
$\implies \dfrac{1}{2} \dfrac{kQq}{R}=\dfrac{1}{2}mv^2$
$\implies v=\sqrt{\dfrac{Qq}{4\pi\epsilon_0 mR}}$

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