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Grade 11Electrostatics

Question no 18 ....................,.............................

Question image for Question no 18 ....................,..............

Chandan Kumar

8 Years agoGrade 11

1 Answer

Eshan

Approved Tutor Answer8 Years ago

Potential energy of the system with charge at the surface of the sphere= $\dfrac{kQq}{R}$ .

Potential energy of the system with charge at the center of sphere= $\dfrac{3}{2}\dfrac{kQq}{R}$

From law of conservation of energy, the gain in electrostatic potential energy=loss in kinetic energy of charge
$\implies \dfrac{3}{2}\dfrac{kQq}{R}-\dfrac{kQq}{R}=\dfrac{1}{2}mv^2$
$\implies \dfrac{1}{2} \dfrac{kQq}{R}=\dfrac{1}{2}mv^2$
$\implies v=\sqrt{\dfrac{Qq}{4\pi\epsilon_0 mR}}$

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