Electrostatics> Q .1 dt 5 Oct 17: *Two point charges are ...

Q .1 dt 5 Oct 17: Two point charges are separated by certain distance in air medium & experiences a force of F newton. If the charge strength of each charge is increased by 20% and distance between them reduced by 10 % ,what will be new force in terms of F ?

Saikat mallick , 8 Years ago

Grade 12th pass

1 Answers

Shailendra Kumar Sharma

Last Activity: 8 Years ago

F=kq₁q₂/r²

Now the charges are increased by 20% and distance reduced by 10%

F*= k(1.2q₁)(1.2q₂)/(.9r)² =1.6kq₁q₂/r²
So F* =1.6F

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Electrostatics> Q .1 dt 5 Oct 17: *Two point charges are ...

Q .1 dt 5 Oct 17: *Two point charges are separated by certain distance in air medium & experiences a force of F newton. If the charge strength of each charge is increased by 20% and distance between them reduced by 10 % ,what will be new force in terms of F ?*

Saikat mallick , 8 Years ago

Shailendra Kumar Sharma

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