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plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz solve question no 28

plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz solve question no 28

Question Image
Grade:11

1 Answers

Eshan
askIITians Faculty 2095 Points
2 years ago
568-1847_Untitled.png
From figure, sin\theta=\dfrac{0.14}{0.5}=0.28
From equilibrium, Tsin\theta=F_{el}
Tcos\theta=mg
\implies F_{el}=mg tan\theta \implies \dfrac{1}{4\pi\epsilon_0}\dfrac{q^2}{(0.28)^2}=10^{-5}\times 10\times 0.29
\implies q=1.58\times 10^{-8}C

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