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Grade 11Electrostatics

plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz solve question no 28

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Profile image of YASH AHUJA
8 Years agoGrade 11
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1 Answer

Profile image of Eshan
8 Years ago
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From figure, sin\theta=\dfrac{0.14}{0.5}=0.28
From equilibrium, Tsin\theta=F_{el}
Tcos\theta=mg
\implies F_{el}=mg tan\theta \implies \dfrac{1}{4\pi\epsilon_0}\dfrac{q^2}{(0.28)^2}=10^{-5}\times 10\times 0.29
\implies q=1.58\times 10^{-8}C

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