B.giridharnaidu
Last Activity: 7 Years ago
n =20 first of all u have to draw circuit diagram. Clearly it`s an unbalanced Wheatstone bridge circuit. Now connect a battery of voltage v across the endpoints of the circuit . Withdraw an amount of charge Q from the positive terminal of the battery. At the junction it divides into two amounts of charges. Say them as x and y . And the charge on the topleft capacitor and the right bottom capacitor are equal . In the same way the charge on the left bottom capacitor and right top capacitor. The most important thing is the direction of charge flows in the middle capacitor is from bottom to top. Now you can simplify the circuit by using kirchoff laws. And finally find the ratio of total charge and voltage applied across the ends . The ratio is the resultant capacitance of the circuit. Capacitance total =20/7micro farad