Please solve this question....An electric field of 4×10^4 Vm^-1 is introduced between the plates, 0.04 m apart, of a parallel plate capacitor. After removing the battery, an uncharged metal plate of thickness 0.01 m is introduced between them. If V1 be the potential difference, before introducing the plate, V2 be the potential difference, if an identical dielectric slab of dielectric constant 4, is introduced in place of metal plate. Then the ratio V1:V2:V3 is

Nithish Kumar , 5 Years ago

Grade 12