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Grade 12th passElectrostatics

Please please please explain this question to me I am in great need for this.A point charge Q is placed at the centre of a hollow uniformly charged sphere of radius R and charge Q.The energy of the system is
Ans-3KQ²/2R

Kaushki

7 Years agoGrade 12th pass

1 Answer

Kapil Khare

7 Years ago

Total energy of the system = Interaction energy of sphere and point charge + Self energy of the Hollow sphere

Self energy of the hollow sphere containing the charge Q = KQ²/(2R)

Potential at the centre of sphere due to charge on hollow sphere = KQ/R

$\implies$ Interaction energy between sphere and the point charge = KQ²/R

$\implies$ Total energy of the system = KQ²/(2R) + KQ²/R

$\implies$ T.E. = 3KQ²/(2R)

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