#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# Please please please explain this question to me I am in great need for this.A point charge Q is placed at the centre of a hollow uniformly charged sphere of radius R and charge Q.The energy of the system isAns-3KQ2/2R

Kapil Khare
80 Points
2 years ago
Total energy of the system = Interaction energy of sphere and point charge + Self energy of the Hollow sphere

Self energy of the hollow sphere containing the charge Q = KQ2/(2R)
Potential at the centre of sphere due to charge on hollow sphere = KQ/R
$\implies$ Interaction energy between sphere and the point charge = KQ2/R

$\implies$ Total  energy of the system = KQ2/(2R) + KQ2/R
$\implies$ T.E. = 3KQ2/(2R)