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Grade 12Electrostatics

One fourth of a sphere of radius R is removed as shown in figure . an electric current E exists parallel to the xy plane . Find the flux through the remaining curved part

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Profile image of manan
8 Years agoGrade 12
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Profile image of Khimraj
ApprovedApproved Tutor Answer8 Years ago
The electric flux through closed surface is zero.
flux through plane surface + flux through curved surface =0
(\pi R^{2}/2)*(E/\sqrt{2})*cos180 + (\pi R^{2}/2)*(E/\sqrt{2})*cos180 + flux through curved surface =0
- (\pi R^{2})*(E/\sqrt{2}) + flux through curved surface =0
flux through curved surface = (\pi R^{2}E/\sqrt{2}).
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