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# If V = 2x-y+a, find E(x,y,z). Find E(1,0,1) and magnitude of E.

Samyak Jain
333 Points
2 years ago
V = 2x – y + a,  here I’m asssuming a to be constant since it’s not specified.
We know E = – ($\dpi{100} \delta$V / $\dpi{100} \delta$x)i –  ($\dpi{100} \delta$V / $\dpi{100} \delta$y)j – ($\dpi{100} \delta$V / $\dpi{100} \delta$z)k.
$\dpi{100} \therefore$  E(x,y,z)  =  – 2 i – ( – 1) j  =  – 2 i + j
i.e. here the electric field is a uniform.
So, E(1,0,1)  =  – 2 i + j
Magnitude of E is $\dpi{100} \sqrt{(-2)^2 + 1^2 +0^2}$ = $\dpi{100} \sqrt{5}$.