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# if u have several 2 micro faraday capacitors each capable of withstanding 200V without breakdown how would you assemble a combination that has an equivalent capacitance pf 0.4 micro faraday withstanding 1000V ?

Arun
25763 Points
one year ago
Put five such capacitors in series. Then, the equivalent capacitance is
2.0X10^(-6)F/5 = 0.40X10^(-6)F.

With each capacitor taking a 200-V potential difference, the equivalent capacitor can withstand 1000 V.

(b) As one possibility, you can take three identical arrays of capacitors, each array being a five-capacitor combination described in part (a) above, and hook up the arrays in parallel. The equivalent capacitance is now Ceq = 3(0.40X10^(-6)F) = 1.2X10^(-6)F. With each capacitor taking a 200-V potential difference, the equivalent capacitor can withstand 1000 V.