If n identical water drops assumed spherical each charged to a potential difference U coalesce to a single drop, the potential energy of the single drop is (assume that drops are uniformly charged):plzz explain n^(1/3) U n^(2/3) U n^(4/3) U n^(5/3)U

Question

Arun · Answer

Let potential f 1 drop = Kq/r =U

Volume of n drops = volume of bigger drop

n 4/3 pi (r)^3 = 4/3 pi (R)^3

Therefore , R = ( (n)^1/3) r

also charge remains conserved

charge on 1 drop = q

charge on big drop containing n drops = (nq)

Therefore potential on big drop = K (nq)/ ((n)^1/3)r

Mithilesh kumar · Answer

U=qV=kqQ/r Also 4/3 pi R3 =4/3 pi r3 n so, R=n1/3 r U’=knqnQ/R=kn2qQ/n1/3r=n5/3U hence, potential energy of the bigger drop is n5/3 times the potential energy of the smaller one.

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If n identical water drops assumed spherical each charged to a potential difference U coalesce to a single drop, the potential energy of the single drop is (assume that drops are uniformly charged):plzz explain n^(1/3) U n^(2/3) U n^(4/3) U n^(5/3)U

If n identical water drops assumed spherical each charged to a potential difference U coalesce to a single drop, the potential energy of the single drop is (assume that drops are uniformly charged):plzz explain

n^(1/3) U

n^(2/3) U

n^(4/3) U

n^(5/3)U

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