Vikas TU
Last Activity: 7 Years ago
Dear Student,
Here we accept that r and R be the radii of the individual mercury drop and the mixed
drop.
Volume of the blended drop = 4πR3/3 = 8 x 4πr3/3
⇒ R = 2r.
Give q a chance to be the charge on every mercury drop and Q = 8q be the charge on the blended drop.
V = kq/r = 20 V
V' = kQ/R
= k. 8q/(2r)
= 4 kq/r
= 4 x 20 V = 80 V.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
