×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
If a spherical conductor of radius 10 cm has potential v at a point distance 5cm from its center, then the potential at point a distance 15 cm from the centre will be

```
3 years ago

Arun
25768 Points
```							Dear Haresh The potential inside a conductor is the same everywhere (if it wasn't, potential differences would exist and currents would flow internally until the charges redistributed and made the internal potential the same everywhere). So everywhere, including the surface, of the conductor is at a potential of V. Outside the sphere, the potential is given by k/rThis means the external potential is inversely proportional to distance from centre. 15cm is 3/2 times bigger than the radius (10cm), so the potential at 15cm is 3/2 times smaller than the potential at the surface. Potential = V/(3/2) = (2/3)V RegardsArun (AskIITians Forum Expert)
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Electrostatics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions