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I am unable to solve questions 2 and 3.please help.hope to to get answer soon
Always use this method to solve the question similar to this:Initial charge across capacitor 100 pF,Q = CV => 100 x 10^-12 x 24 = > 24 x 10^10 C.Now when connected with other Capacitor 0f 20 pF then assume charges Q and Q-x in capicitors resecrvely.Thus,(Q-x)/C1 – x/C2 = 0we get,x = QC2/(C2 – C1)putting the values we get,x = 6 x 10^-10 C.we get Q-x = 18 x 10^-10 C.Hence,Voltage = 18 x 10^-10/100 x 10^-12 => 18 V
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