I am unable to solve questions 2 and 3.please help.hope to to get answer soon

Question

Vikas TU · Answer

Always use this method to solve the question similar to this: Initial charge across capacitor 100 pF, Q = CV => 100 x 10^-12 x 24 = > 24 x 10^10 C. Now when connected with other Capacitor 0f 20 pF then assume charges Q and Q-x in capicitors resecrvely. Thus, (Q-x)/C1 – x/C2 = 0 we get, x = QC2/(C2 – C1) putting the values we get, x = 6 x 10^-10 C. we get Q-x = 18 x 10^-10 C. Hence, Voltage = 18 x 10^-10/100 x 10^-12 => 18 V

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I am unable to solve questions 2 and 3.please help.hope to to get answer soon

I am unable to solve questions 2 and 3.please help.hope to to get answer soon

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