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Electrostatics

How to solve the following problem:
Very large rod, with constant longitudinal charge density Q’, is set in vacuum parallel to very large conductive ribbon with width ‘a’ , where height between them is ‘a/2’ . If the surface charge density of a ribbon is ‘σ‘, calculate longitudinal force on a rod.
Thanks for reply.

Profile image of Nemanja Grubor
11 Years agoGrade
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1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To tackle the problem of calculating the longitudinal force on a charged rod placed parallel to a conductive ribbon, we need to break it down into manageable steps. The setup involves a rod with a uniform charge density \( Q' \) and a conductive ribbon with a surface charge density \( \sigma \). The distance between the rod and the ribbon is \( a/2 \). Let’s go through the solution systematically.

Understanding the Electric Field

First, we need to determine the electric field produced by the conductive ribbon. Since the ribbon is conductive, it will create an electric field in the space around it due to its surface charge density \( \sigma \).

Electric Field Due to the Conductive Ribbon

The electric field \( E \) generated by an infinite plane sheet of charge is given by the formula:

  • E = σ / (2ε₀)

Here, \( ε₀ \) is the permittivity of free space. Since the ribbon is conductive, it will create an electric field on both sides, but we are only interested in the field in the region between the rod and the ribbon. Therefore, the effective electric field in the region between the rod and the ribbon is:

  • E = σ / (2ε₀)

Force on the Charged Rod

Next, we can calculate the force acting on the rod due to this electric field. The force \( F \) experienced by a charge \( Q \) in an electric field \( E \) is given by:

  • F = Q * E

In our case, the charge \( Q \) on the rod can be expressed in terms of its charge density \( Q' \) and its length \( L \):

  • Q = Q' * L

Combining the Equations

Substituting the expression for \( Q \) into the force equation gives us:

  • F = (Q' * L) * (σ / (2ε₀))

Now, we can simplify this to find the total force acting on the rod:

  • F = (Q' * σ * L) / (2ε₀)

Final Expression for the Longitudinal Force

Thus, the longitudinal force acting on the rod due to the electric field created by the conductive ribbon is:

  • F = (Q' * σ * L) / (2ε₀)

This formula encapsulates the relationship between the charge density of the rod, the surface charge density of the ribbon, and the length of the rod, providing a clear method to calculate the force in this electrostatic scenario.

In summary, by understanding the electric field generated by the conductive ribbon and applying the force equation for a charged object in an electric field, we can derive the longitudinal force acting on the rod. If you have any further questions or need clarification on any part of this process, feel free to ask!