Half of a semicircle of radius r has q charge distributed uniformly over it and -q charge uniformly over other half of it find electric field magnitude at centre _JUST give answer

The electric field magnitude at the center of the semicircle is given by the formula: E = (k * q) / (2 * r^2), where k is Coulomb's constant. This results from the contributions of both the positive and negative charges distributed along the semicircle.