0

Guest

Courses New

GUYS PLEASE REPLY ASAP!!!!!!!!!!! WHAT IS THE ANSWER?

GUYS PLEASE REPLY ASAP!!!!!!!!!!!   WHAT IS THE ANSWER?

Question Image
Grade:11

1 Answers

Eshan
askIITians Faculty 2095 Points
5 years ago
When 1 is connected, capacitor C1 gets charged to potential 60V attaining a charge equal to60\mu C. When 1 is diconnected and 2 is connected, the capacitor C1 starts to get discharged into an effective capacitance of2\mu F(formed by series combination of C2 and C3).

From Kirchoff’s voltage law, the voltage across the two capacitors will be same. Thus
\dfrac{Q_1}{C_1}=\dfrac{Q_{eff}}{C_eff} \implies \dfrac{Q_1}{Q_{eff}}=\dfrac{C_1}{C_eff}=\dfrac{1}{2}

The initial charge attained by C1 has actually been divided into capacitancesC_1andC_{eff}.
ThusQ_1+Q_{eff}=60\mu C

HenceQ_{eff}=Q_2+Q_3=40\mu C

Think You Can Provide A Better Answer ?

Other Related Questions on Electrostatics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More