Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

good morning sir please explain this problem problem is given in image please explain it fast

Ravneet
104 Points
3 years ago
WHEN THE ELECTRIC FIELD IS APPLIED,
• IT WILL PRODUCE TORQUE (there will be friction also due to rough horizontal surface )
• THE NET ELECTRIC FORCE WILL BE ZERO.
torque = R . F. sinx                                              where F is qE but q is not given
so q = (lambda)(R.dx)        where x is the angle where the charge is distributed
TARGET: TO find TORQUE independent of x (angle)
torque = ∫ (lambda . R .dx ) E sinx
limit of integration will be 0 to pi/ 2 and this torque will be multiply by 2 becouse the torque is produced by both + and – charge
torque = 2 X ∫ (lambda . R .dx ) E sinx             limit of integration will be 0 to pi/ 2
ON SOLVING, WE GET
torque = (2)( lambda)(  E )( R2)
AS THE MOTION IS PURE ROLLING,
torque – (torque produced by frictional force ) = (moment of inertia ) (alpha )
where alpha = angular acceleration = f/(mR)

(2)( lambda)(  E )( R2)    –  f(R)    =   I (ALPHA )
(2)( lambda)(  E )( R2)    –  f(R)    =    I X f/(mR)
PUT I = mR2
and sove for f (frictional force)