Good morning sir..Answer is 2nd option.Explain sir.
raju nagula , 6 Years ago
Grade
Electrostatics> Good morning sir.. Answer is 2nd option. ...
2 Answers
Khimraj
Last Activity: 6 Years ago
Eletric field intensity is given by kq/r2
SInce both charge are equal and at are equal distance from point.
So magnitude of electric field due to these charge will be equal but will be in opposite direction.
So resultant electric field intensity at midpoint will be zero.
Hope it clears.
Khimraj
Last Activity: 6 Years ago
sorry i understand both charge of same sign.
If both are of opposite sign then direction should be toward -ve charge.
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free
Enter text here...
Other Related Questions on Electrostatics
Electrostatics question based on earthing of spherical shell
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)
an object has a charge of 2c and gains 10^19 electrons. the net chaarge on the object becomes??
Electrostatics
1 Answer Available
Last Activity: 2 Year ago(s)
A wire with a linear charge density lambda forms a quarter of a cjrclenof radius R and is placed asa shown in thefigure with its centre of curvature at the origin O the electric field at O will be
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)
Find the value of q so that system remains in equilibrium.. figure attached below
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)
Find the value of q so that system remains in equilibrium
Electrostatics
0 Answer Available
Last Activity: 2 Year ago(s)