Grade 12th passElectrostatics

Four particles each having a charge q, are placed on four vertices of a regular pentagon.The distance of each corner from the center is ‘a’ .Find the electric field at the centre of the pentagon.

Aamina

10 Years agoGrade 12th pass

3 Answers

krishna priya

Approved Tutor Answer10 Years ago

If there were 5 charges at each corner then the net electric field at the centre would be 0 since it is a regular polygon .the electric field due to 4 charges will be equal and opposite to the electric field due to the 5^th charge so as to make the net electric field at the centre to be 0

Hence electric field at the centre due to 4 charges = electric field at the centre due to the 5^th charge

=q/4 $\pi$ $\epsilon$ ₀a²

Ganesh

7 Years ago

If there is a charge at 5th vertex of polygon

F1+F2+F3+F4+F5=0........eq(1)

From above question there is no charge at 5th vertex so F5 should be eliminated from eq(1)

F1+F2+F3+F4+F5-F5=-F5

therefore F1+F2+F3+F4=-F5

Net force at centre is -ve F5 =kq/a²

force at centre of pentagon is equal to -ve of force F5 =

Yash Chourasiya

6 Years ago

Hello Student

If there were 5 charges at each corner then the net electric field at the centre would be 0 because it is a regular polygon.
F₁ + F₂ + F₃ + F₄ + F₅ = 0........eq(1)

F₁+ F₂ + F₃ + F₄ = -F₅

Electric field at centre due to the 5thcharge₌q/4 πϵ₀a²
(Negative sign indicates the direction)

I hope this answer will help you.