Four charges of +10 μC,-10 μC,+5 μC, -5 μC are the placed at the four corners of a square of side 20mm.Calculate the force acting on a charge +2 μC placed at the point of intersection of the diagonals of the square?

Question

mansi · Answer

the force acting on the given charge is 636.39 N which can be calculated by using formula F=(k*q1*q2)/r^2 for two pair of charges and then addinf all the forces vectorically

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Four charges of +10 μC,-10 μC,+5 μC, -5 μC are the placed at the four corners of a square of side 20mm.Calculate the force acting on a charge +2 μC placed at the point of intersection of the diagonals of the square?

Four charges of +10 μC,-10 μC,+5 μC, -5 μC are the placed at the four corners of a square of side 20mm.Calculate the force acting on a charge +2 μC placed at the point of intersection of the diagonals of the square?

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