Vikas TU
Last Activity: 7 Years ago
We have the framework which comprise of 4 point charges +q set at 4 corners of a square . The four of charges will be in balance if add up to electric potential vitality is zero.Hence, = Potential Energy because of all the four sets in which Potential vitality framework charges put at the side of the sides of square+PE because of each one of those sets in which charges are set at finishes of the slanting of square +Potential Energy because of sets shaped by any charge at the corner and charge
Potential Energy of System = 4×1/4πε0 ×q2/a +2×1/4πε0 × q2/a√2 +4×1/4πε0 × qQ/a/√2
Potential Energy of System = 1/4πε0×4q/a [q+q/2√2+Q√2 ]
The framework will be in balance if
Potential Energy of System = 0
1/4πε0 ×(4q/a) [q+ q/2√2+Q√2 ] = 0
q+ q/2√2+Q√2 = 0
Q√2 = −(q+q/2√2 )
Q = −(q/√2 + q/4)
Q = −q((2√2+1 )/4)
Q = −q/4 (2√2 +1)
We have the framework which comprise of 4 point charges +q put at 4 corners of a square . The four of charges will be in balance if add up to electric potential vitality is zero.Hence, = Potential Energy because of all the four sets in which Potential vitality framework charges set at the edge of the sides of square+PE because of every one of those sets in which charges are set at finishes of the askew of square +Potential Energy because of sets shaped by any charge at the corner and charge
Potential Energy of System = 4×1/4πε0 ×q2/a +2×1/4πε0 × q2/a√2 +4×1/4πε0 × qQ/a/√2
Potential Energy of System = 1/4πε0×4q/a [q+q/2√2+Q√2 ]
The framework will be in harmony if
Potential Energy of System = 0
1/4πε0 ×(4q/a) [q+ q/2√2+Q√2 ] = 0
q+ q/2√2+Q√2 = 0
Q√2 = −(q+q/2√2 )
Q = −(q/√2 + q/4)
Q = −q((2√2+1 )/4)
Q = −q/4 (2√2 +1)
