five point charge each +q are placed at the vertical of a regular hexagon of side ‘a’. find the electric field at the centre of the hexagon.

The answer is QA/pi X epsinol X XFor detailed solution

If there were 6 charges at each corner then the net electric field at the centre would be zero since it is a regular hexagon . the electric field due to 5 charges will be equal and opposite to the net electric field due to sixth charge so as to make the net electric field at the centre to be zero . Hence electric field at the centre due to 5 charges is will be equal to electric field at the centre due to sixth charge. F=(kq^2)/a^2