Find the equivalent capacitance of the network given in figure

Here, wheatstone bridge concept will be used...
therefore the capacitor in btw will be redundent and then Two of the above in seriers with ll in below 2 seiers capacitors 
i.e. Ceq = (C/2) +(C/2) = C

its not a balanced wheatstone bridge must be solved using loop rule let charge through on is Q and other Q-x   ceq=Q/V

write v in terms of Q