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find the electric field E at the midpoint/centre of the cube for the given figure

THANGUTURU NIRGUNA , 5 Years ago
Grade 12th pass
anser 2 Answers
Vikas TU

Last Activity: 5 Years ago

Hi 
According to gauss law 
Close integral E.ds = q/epselon 
ds will be equal to Area
So, E = q/6epselon 
 

rajuu kumar

Last Activity: 5 Years ago

As all the charges are same (q), so every charge at one corner will cancel the electric field produced by the charge at the opposite corner and hence net electric field = 0 at the centre.

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