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find the electric field E at the midpoint/centre of the cube for the given figure
Hi According to gauss law Close integral E.ds = q/epselon ds will be equal to AreaSo, E = q/6epselon
As all the charges are same (q), so every charge at one corner will cancel the electric field produced by the charge at the opposite corner and hence net electric field = 0 at the centre.
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