find the electric field E at the midpoint/centre of the cube for the given figure

Question

Vikas TU · Answer

Hi According to gauss law Close integral E.ds = q/epselon ds will be equal to Area So, E = q/6epselon

rajuu kumar · Answer

As all the charges are same (q), so every charge at one corner will cancel the electric field produced by the charge at the opposite corner and hence net electric field = 0 at the centre.

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find the electric field E at the midpoint/centre of the cube for the given figure

find the electric field E at the midpoint/centre of the cube for the given figure

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