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Find force experienced by semicircular rod charged with charge q , placed as shown in fig. Radius of wire is R and line of charge with linear charge density lambda passing through centre and perpendicular to plane of wire

Shubham Gayakwad , 8 Years ago
Grade 12
anser 4 Answers
Matrix 144
2klamba/r×q now as we have calculated the force experienced by a full circle of 2π divide it by π therefore the answer will be 2klamba/rπ×q
Last Activity: 8 Years ago
shubham singh
Answer of this question is lamda /4€R
Last Activity: 8 Years ago
Albin Thomas
(Lamdaq)/(π^2E°R)
thanks
Last Activity: 7 Years ago
ankit singh

Fnet=dqEcosθ
=π/2π/2(πRq)Rdθ2πεRλcosθ
=2π2ε0Rλqπ/2π/2cosθdθ=2π2ε0Rλq[sinθ]π/2π/2
=2π2ε0Rλq[1(1)]=π2ε0Rλq

Last Activity: 5 Years ago
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