Find force experienced by semicircular rod charged with charge q , placed as shown in fig. Radius of wire is R and line of charge with linear charge density lambda passing through centre and perpendicular to plane of wire

Question

Matrix 144 · Answer

2klamba/r×q now as we have calculated the force experienced by a full circle of 2π divide it by π therefore the answer will be 2klamba/rπ×q

shubham singh · Answer

Answer of this question is lamda /4&euro;R

Albin Thomas · Answer

(Lamdaq)/(&pi;^2E&deg;R) thanks

ankit singh · Answer

F n e t ​ = ∫ d q E c o s θ = ∫ − π / 2 π / 2 ​ ( π R q ​ ) R d θ 2 π ε ⋅ R λ ​ c o s θ = 2 π 2 ε 0 ​ R λ q ​ ∫ − π / 2 π / 2 ​ c o s θ d θ = 2 π 2 ε 0 ​ R λ q ​ [ s i n θ ] − π / 2 π / 2 ​ = 2 π 2 ε 0 ​ R λ q ​ [ 1 − ( − 1 ) ] = π 2 ε 0 ​ R λ q ​

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

Find force experienced by semicircular rod charged with charge q , placed as shown in fig. Radius of wire is R and line of charge with linear charge density lambda passing through centre and perpendicular to plane of wire

Find force experienced by semicircular rod charged with charge q , placed as shown in fig. Radius of wire is R and line of charge with linear charge density lambda passing through centre and perpendicular to plane of wire

4 Answers

Fnet=∫dqEcosθ
=∫−π/2π/2(πRq)Rdθ2πε⋅Rλcosθ
=2π2ε0Rλq∫−π/2π/2cosθdθ=2π2ε0Rλq[sinθ]−π/2π/2
=2π2ε0Rλq[1−(−1)]=π2ε0Rλq

Think You Can Provide A Better Answer ?

Other Related Questions on Electrostatics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

Guest

IIT JEE Courses

One Year IIT Programme

Two Year IIT Programme

Crash Course

NEET Courses

One Year NEET Programme

Two Year NEET Programme

One to One

School Board

Live Online classes

Class 11 & 12

Class 9 & 10

Class 6, 7 & 8

Test Series

JEE test series

NEET test series

C.B.S.E test series

Complete Self Study Packages

FULL COURSE

For class 12th

For class 11th

Find force experienced by semicircular rod charged with charge q , placed as shown in fig. Radius of wire is R and line of charge with linear charge density lambda passing through centre and perpendicular to plane of wire

Find force experienced by semicircular rod charged with charge q , placed as shown in fig. Radius of wire is R and line of charge with linear charge density lambda passing through centre and perpendicular to plane of wire

4 Answers

Fnet​=∫dqEcosθ=∫−π/2π/2​(πRq​)Rdθ2πε⋅Rλ​cosθ=2π2ε0​Rλq​∫−π/2π/2​cosθdθ=2π2ε0​Rλq​[sinθ]−π/2π/2​=2π2ε0​Rλq​[1−(−1)]=π2ε0​Rλq​

Think You Can Provide A Better Answer ?

Other Related Questions on Electrostatics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship

Fnet=∫dqEcosθ
=∫−π/2π/2(πRq)Rdθ2πε⋅Rλcosθ
=2π2ε0Rλq∫−π/2π/2cosθdθ=2π2ε0Rλq[sinθ]−π/2π/2
=2π2ε0Rλq[1−(−1)]=π2ε0Rλq