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Grade 12Electrostatics

Find force experienced by semicircular rod charged with charge q , placed as shown in fig. Radius of wire is R and line of charge with linear charge density lambda passing through centre and perpendicular to plane of wire

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Shubham Gayakwad

9 Years agoGrade 12

4 Answers

Matrix 144

8 Years ago

2klamba/r×q now as we have calculated the force experienced by a full circle of 2π divide it by π therefore the answer will be 2klamba/rπ×q

shubham singh

8 Years ago

Answer of this question is lamda /4€R

Albin Thomas

8 Years ago

(Lamdaq)/(π^2E°R)
thanks

ankit singh

5 Years ago

Fnet=∫dqEcosθ
=∫−π/2π/2(πRq)Rdθ2πε⋅Rλcosθ
=2π2ε0Rλq∫−π/2π/2cosθdθ=2π2ε0Rλq[sinθ]−π/2π/2
=2π2ε0Rλq[1−(−1)]=π2ε0Rλq

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