Flag Electrostatics> Exactly midway of a parallel plate capaci...
question mark

Exactly midway of a parallel plate capacitor a charged plate was placed having charge q. The capacitance is connected to a battery of voltage V. The plate is moved perpendicular to itself by a distance x, What is the charge flowing through the external circuit of the capacitor, if the distance between its plates equal to d?

Abraham Benny , 7 Years ago
Grade 11
anser 1 Answers
Eshan
The plate kept between a capacitor divides the capacitor into two capacitors connected in series.

For the intial configuration, the capacitance of each half of the capacitor is\dfrac{A\epsilon_0}{d/2}=\dfrac{2A\epsilon_0}{d}
Hence when connected the two capacitors are connected in series, the overall capacitance becomes\dfrac{A\epsilon_0}{d}.

When the plate is moved by distancex, the capacitane of one side of the capacitor becomesC_1=\dfrac{A\epsilon_0}{\dfrac{d}{2}-x}
The capacitance of other half becomesC_2=\dfrac{A\epsilon_0}{\dfrac{d}{2}+x}
Hence the total capacitance becomes\dfrac{C_1C_2}{C_1+C_2}=\dfrac{A\epsilon_0}{d}
Therefore, the capacitance of the system does not change even by moving the plate. So, the charge over the capacitor does not change at any time and so no current flows through the external circuit.
Last Activity: 7 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments