Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
et mass of both the charges is m and charge on both the charges is q
take a sphere which is at height h1 two forces act on it
force of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g hence
h1=1/2(g+qe/m)t^2
let t is time taken by small sphere in travelling distance
l=vt , t=l/v
let x is distance travelled by second sphere
forces acting on it
force of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m)
X=1/2(g-qe/m)t^2
height at this instant is h2-x
x=gl^2/v^2-h1
hence height is h2-(gl^2/v^2)
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !