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Grade 10Electrostatics

dear sir,
Find equivalent capacitance between A and B in the combination given below : each capacitor is of 2 µF..
Thanks and Regards
Murali..

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9 Years agoGrade 10
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1 Answer

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ApprovedApproved Tutor Answer1 Year ago

To find the equivalent capacitance between points A and B in a circuit with capacitors, we first need to know how the capacitors are arranged—whether they are in series, parallel, or a combination of both. Since you mentioned that each capacitor is 2 µF, let's explore how to calculate the equivalent capacitance based on different configurations.

Capacitors in Series

When capacitors are connected in series, the total or equivalent capacitance (C_eq) can be calculated using the formula:

  • 1/C_eq = 1/C1 + 1/C2 + 1/C3 + ...

For example, if you have two capacitors of 2 µF each in series, the calculation would be:

  • 1/C_eq = 1/2 + 1/2 = 1/1 = 1 µF

This means the equivalent capacitance for two 2 µF capacitors in series is 1 µF.

Capacitors in Parallel

In contrast, when capacitors are connected in parallel, the equivalent capacitance is simply the sum of their capacitances:

  • C_eq = C1 + C2 + C3 + ...

For instance, if you have two capacitors of 2 µF each in parallel, the equivalent capacitance would be:

  • C_eq = 2 + 2 = 4 µF

This indicates that the equivalent capacitance for two 2 µF capacitors in parallel is 4 µF.

Combining Series and Parallel

In many circuits, capacitors are arranged in a combination of series and parallel. To find the equivalent capacitance in such cases, you can break the circuit down into simpler parts. First, calculate the equivalent capacitance for the capacitors in series, then treat that result as a single capacitor and add it to the capacitors in parallel, or vice versa.

Example Calculation

Imagine a scenario where you have two capacitors in series (each 2 µF) connected in parallel with another capacitor (also 2 µF). Here’s how you would calculate the equivalent capacitance:

  • First, find the equivalent capacitance of the two capacitors in series:
    • 1/C_eq_series = 1/2 + 1/2 = 1 µF
  • Now, this equivalent capacitance (1 µF) is in parallel with the third capacitor (2 µF):
    • C_eq_total = 1 + 2 = 3 µF

Final Thoughts

To summarize, the method to find the equivalent capacitance depends on the arrangement of the capacitors. By applying the appropriate formulas for series and parallel combinations, you can systematically determine the total capacitance between points A and B. If you have a specific configuration in mind, feel free to share, and we can work through it together!