Vikas TU
Last Activity: 7 Years ago
Dear Student,
At the point when a charge q is set at the side of the 3D shape it implies the flux is disseminated among 8 3D squares of same measurement in light of the fact that in one corner there can be 8 cubes.(You need to envision it, Similar to strong state where one corner iota is shared by 7 other cross section. Add up to grid 3D squares =8).
So the flux connected with one solid shape is (1/8)q/e
The flux leaving the charge will pass just to 3 appearances of the block since alternate countenances are parallel.
In this way, Flux=1/3 x 1/8 x q/e
=1/24e
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)