Grade 12th passElectrostatics

Calculate the voltage needed to balance an oil drop carrying 10 electrons between the plates of capacitor 5mm apart.The mass of the drop is 3x10^-16kg and g=10ms^-2.

Atal Tiwari

11 Years agoGrade 12th pass

3 Answers

Mallikarjun Maram

11 Years ago

The gravitational force on the oil drop = mg = 3 x 10^-16 x 10 = 3 x 10^-15 N.

Magnitude of the electrostatic force needed balance this force is given by

E = mg/10e = (3 x 10^-15) / (10 x 1.6 x 10^-19) = 0.1875 x 10⁴ V/m.

Voltage across the places of the capacitor is then given by

V = Ed = 0.1875 x 10⁴ x 5 x 10^-3 = 9.375 Volts.

Krish Gupta

6 Years ago

The gravitational force on the oil drop = mg = 3 x 10^-16 x 10 = 3 x 10^-15 N.

Magnitude of the electrostatic force needed balance this force is given by

E = mg/10e = (3 x 10^-15) / (10 x 1.6 x 10^-19) = 0.1875 x 10⁴ V/m.

Voltage across the places of the capacitor is then given by

V = Ed = 0.1875 x 10⁴ x 5 x 10^-3 = 9.375 Volts.

Thanks , hope it helps.

Kushagra Madhukar

5 Years ago

Dear student,

Please find the solution to your problem.

For the oil drop to be in balance, the electrostatic force and the gravitational force need to be equal.

Hence, qE = mg

or, q x V/d = mg

or, V = mgd/q = mgd/10e

or, V = (3 x 10^-16 x 10 x 5 x 10^-3)/ (10 x 1.6 x 10^-19)

= 9.375 Volts

Hope it helps.

Thanks and regards,

Kushagra

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View all Questions

Calculate the voltage needed to balance an oil drop carrying 10 electrons between the plates of capacitor 5mm apart.The mass of the drop is 3x10-16kg and g=10ms-2.

Atal Tiwari

3 Answers

Mallikarjun Maram

Krish Gupta

Kushagra Madhukar

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Calculate the voltage needed to balance an oil drop carrying 10 electrons between the plates of capacitor 5mm apart.The mass of the drop is 3x10^-16kg and g=10ms^-2.