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answer is coming k2q/a^2....can anyone answer ​Here electric field is asked at the centre of the square ​ ​

answer is coming k2q/a^2....can anyone answer
​Here electric field is asked at the centre of the square
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Grade:12th pass

1 Answers

Eshan
askIITians Faculty 2095 Points
4 years ago
Dear student,

The electric field at the center due to the two charges placed diagonally opposite will cancel each other. Thus the electric field be due to only one of the charges and equal to

\dfrac{kq}{r^2}=\dfrac{kq}{(\dfrac{a}{\sqrt{2}})^2}=\dfrac{2kq}{a^2}

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