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`        An infinitely long wire is kept along z=-infinity axis from z=+infinity, having uniform linear charge density 10/9nC/m. The electric field at a point ( 6cm, 8cm, 10cm ) will be `
3 months ago

```							E= (lambda)/(2pi epsilon_(0)d)= (2K lambda)/(d)` `=(2xx9xx10^(9)xx(10//9)xx10^(-9))/(10xx10^(-2))=200 V//m` As field is radial , out, there is no component of it in `Z` direction.  `vec(E )=(200 cos 53^(@) hat (i)+200 sin 53^(@)hat(j))V//m` `=(200xx(3)/(5)hat(i)+200xx(4)/(5)hat(j))= (120hat(j)+160hat(j))V//m`
```
3 months ago
```							electric field due to infinite rod is equal to (charge density)/(2πεr) where r is dist of point from rod.....here sincerod is along z axis therefore r will be 10 cm.....therefore (10/9)*10^-9/2πε10*10^-2=200k V/m
```
3 months ago
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