An electric dipole of charges 2×10-6c,-2×10-6c are separated by a distance 1cm. Calculate the electric field due to dipole at a point on its(i)axial line 1m from its centre (ii)equatorial line 1m from its centre

dipole moment of dipole p = q*l = 2*10-6*1*10-2Cm = 2*10-8Cm electirc field at axial line is given by E = 2Kp/r3 = 2*9*109*2*10-8/13 = 360 N/C electric field at equitorial line is given by E = Kp/r3 = 180N/C.Hope it clears. If you like answer then please approve it.