An air capacitor is made from two flat parallel plates 0.5 apart , the magnitude of charge on earth plate is 0.01πc when the potential difference is 200v. Calculate (a) the capacitance (b) the area of the plate

Question

Mohd Shahnawaz · Answer

c＝q/v here q＝ 0.01nc ,q＝10 to the power -11pd is 200 volt so the ans is 5into 10 to the power － 14 of first part

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An air capacitor is made from two flat parallel plates 0.5 apart , the magnitude of charge on earth plate is 0.01πc when the potential difference is 200v. Calculate (a) the capacitance (b) the area of the plate

An air capacitor is made from two flat parallel plates 0.5 apart , the magnitude of charge on earth plate is 0.01πc when the potential difference is 200v. Calculate (a) the capacitance
(b) the area of the plate

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An air capacitor is made from two flat parallel plates 0.5 apart , the magnitude of charge on earth plate is 0.01πc when the potential difference is 200v. Calculate (a) the capacitance (b) the area of the plate

An air capacitor is made from two flat parallel plates 0.5 apart , the magnitude of charge on earth plate is 0.01πc when the potential difference is 200v. Calculate (a) the capacitance(b) the area of the plate

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An air capacitor is made from two flat parallel plates 0.5 apart , the magnitude of charge on earth plate is 0.01πc when the potential difference is 200v. Calculate (a) the capacitance
(b) the area of the plate