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According to quantisation of charge, charges exist as integral multiples of e. but quarks are known to have charges 2/3e,-1/3e. therefore, is this a violation of quantisation of charge or else what`s the explanation??

NANDA , 11 Years ago
Grade 12
anser 1 Answers
Sunil Kumar FP

Last Activity: 11 Years ago

this is because quark cannot be detected in isolation.quark n
basically clump together to form hadron which is basically of two type meson and baryon.this is called quark cnfinement.meson qnd baryon both have charge in integral multiple of charge on electron.so no violation of charge quantisation.

thanks and regards
sunil kr
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