0

Guest

Courses New

According to quantisation of charge, charges exist as integral multiples of e. but quarks are known to have charges 2/3e,-1/3e. therefore, is this a violation of quantisation of charge or else what`s the explanation??

According to quantisation of charge, charges exist as integral multiples of e.
but quarks are known to have charges 2/3e,-1/3e.
therefore, is this a violation of quantisation of charge or else what`s the explanation??

Grade:12

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
this is because quark cannot be detected in isolation.quark n
basically clump together to form hadron which is basically of two type meson and baryon.this is called quark cnfinement.meson qnd baryon both have charge in integral multiple of charge on electron.so no violation of charge quantisation.

thanks and regards
sunil kr
askIItian faculty

Think You Can Provide A Better Answer ?

Other Related Questions on Electrostatics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More